Question. Rank Na, Mg and Cl by atomic radius and by first ionization energy, and justify the ranking.
Ranking. All three are in period 3, so their outer electrons are in the n = 3 shell with 10 core electrons shielding the nucleus. Nuclear charge rises from 11 (Na) to 12 (Mg) to 17 (Cl). Radius: Na > Mg > Cl. First ionization energy: Na < Mg < Cl.
Data. Typical atomic radii are about 186 pm (Na), 160 pm (Mg) and 99 pm (Cl). First ionization energies are 496, 738 and 1251 kJ/mol. The numbers confirm the ranking.
Justification for a free response. "Cl has more protons than Na while its valence electrons are in the same shell with the same core shielding, so the valence electrons in Cl experience a greater Coulombic attraction. They are held closer to the nucleus (smaller radius) and require more energy to remove (higher ionization energy)."
Check it in the simulator. Select Atomic radius and tap Na, Mg and Cl in turn: the readout shows 186 pm, 160 pm and 99 pm (79%, 66% and 34% of the range shown). Switch to Ionization energy and tap them again: 496, 738 and 1251 kJ/mol. Now compare down group 1 for radius: Li 152 pm, Na 186 pm, K 227 pm. Then tap Al in Ionization energy mode: 578 kJ/mol, lower than Mg's 738, one of the exceptions described above, and visible as a lighter cell next to Mg. One more real exception shows in Atomic radius mode: gallium (135 pm) is slightly smaller than aluminium (143 pm), because the ten 3d electrons added before Ga shield poorly and raise its effective nuclear charge.